php start.php start -d 出錯,這個怎么處理?
問題描述
這里寫描述
fopen(): Filename cannot be empty in file /www/wwwroot/webman_axb_api/vendor/workerman/workerman/Worker.php on line 1294
PHP Fatal error: Uncaught Exception: Can not open stdoutFile in /www/wwwroot/webman_axb_api/vendor/workerman/workerman/Worker.php:1325
Stack trace:
0 /www/wwwroot/webman_axb_api/vendor/workerman/workerman/Worker.php(1599): Workerman\Worker::resetStd()
1 /www/wwwroot/webman_axb_api/vendor/workerman/workerman/Worker.php(1426): Workerman\Worker::forkOneWorkerForLinux(Object(Workerman\Worker))
2 /www/wwwroot/webman_axb_api/vendor/workerman/workerman/Worker.php(1400): Workerman\Worker::forkWorkersForLinux()
3 /www/wwwroot/webman_axb_api/vendor/workerman/workerman/Worker.php(560): Workerman\Worker::forkWorkers()
4 /www/wwwroot/webman_axb_api/vendor/workerman/webman-framework/src/support/App.php(131): Workerman\Worker::runAll()
5 /www/wwwroot/webman_axb_api/start.php(4): support\App::run()
6 {main}
thrown in /www/wwwroot/webman_axb_api/vendor/workerman/workerman/Worker.php on line 1325
1個回答
年代過于久遠,無法發(fā)表回答